Advanced Math
~35% of the section. Quadratics, exponentials, polynomials, and function notation.
2 min read
The other 35%, and where most of the score ceiling lives. If you want a 700+, this is the folder to over-invest in.
Quadratics — three forms, three uses
| Form | Reads off |
|---|---|
Standard ax² + bx + c | y-intercept is c |
Factored a(x − p)(x − q) | roots are p and q |
Vertex a(x − h)² + k | vertex is (h, k) |
The test asks "which form best shows the ___" constantly. The answer is always the form that has the thing sitting in it as a number.
The quadratic formula is not on the reference sheet: x = (−b ± √(b² − 4ac)) / 2a. Memorise it.
The discriminant b² − 4ac gives the number of real solutions without solving:
- > 0 → two real solutions
- = 0 → exactly one
- < 0 → none
Questions asking "for what value of k does this have exactly one solution" are discriminant questions. Set it to zero.
Vertex x-coordinate = −b/2a. That's the axis of symmetry, the maximum or minimum, and the answer to most "what value of x maximises..." questions.
Exponents and radicals
xᵃ · xᵇ = xᵃ⁺ᵇxᵃ / xᵇ = xᵃ⁻ᵇ(xᵃ)ᵇ = xᵃᵇx⁻ᵃ = 1/xᵃx^(a/b) = ᵇ√(xᵃ)x⁰ = 1
Exponential growth and decay: y = a(1 ± r)ᵗ — a is the initial amount, r the rate per period, t the number of periods. If the period isn't 1 (compounded monthly over t years), it's a(1 + r/n)^(nt).
Linear vs. exponential is a recurring question: linear changes by a constant amount per step; exponential changes by a constant factor. Check a table by subtracting consecutive values (constant → linear) and then dividing them (constant → exponential).
Polynomials
- Factor theorem: if
p(a) = 0then(x − a)is a factor, and a is an x-intercept. These three statements are the same statement, and the test rotates between them. - Remainder theorem: dividing
p(x)by(x − a)leaves remainderp(a). - End behaviour is set by the leading term's degree and sign.
Function notation
f(3) means substitute 3 for x. f(g(x)) means evaluate g first, then feed the result into f. Work inside out, and write the intermediate value down — composed-function errors are almost all bookkeeping.
Transformations of f(x):
f(x) + k→ up kf(x + k)→ left k (not right — this is the one everyone reverses)−f(x)→ flip over the x-axisf(−x)→ flip over the y-axis
Rational equations
Multiply through by the denominator, solve, then check for extraneous solutions — any value that makes an original denominator zero is not a solution, however cleanly it fell out of the algebra. The test includes it as a wrong answer every time.